Question

A body dimensions us 1.5 m× 1 m × 2 m weight 3000 kg in water. Its specific gravity is

Answer 1

i have two answer of this question
first
Sp gr. = density of object ÷ density of std fluid.

Therefore density of object is 3000/3 = 1000.

Hence sp gr = 1000 ÷ 1000 = 1.

second Weight
in air=weight in water + buoyant force.

=3000+(sp gr of water* g * volume displaced).

=3000+(1000*10*3).

=33000 N.

So,
Mass of body=33000/10.
=3300 kg.

Density=3300/3.
=1100.

Sp gr.=1100/1000.
=1.1.

Answer 2

use

formula for specific gravity

=mass density of the fluid/mass density of the standard fluid

mass density= mass/volume