Question

a body dropped from a height h reached the ground in time t the time taken by it to reach a point which is at a height H/2 from the ground is

Answer 1

s=ut+12at2

Since the ball was at rest before dropping, u=0

So in the given case, we have,

h=12gT2

So, at T/2, it would have travelled h/4 distance, which means the height of the ball would be 3h/4.