A body dropped from atop of a tower covers a distance7x in last secondof its journey where x is distance covers in first second.how much time doea it take to reach the ground
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t=4 seconds .Pls mark it as brainlist.
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Answer: 3.5 sec
Explanation: distance covered by a free falling body in one sec = 5
( from s = Vit ± 1/2 × a × t (square)
putting a = g , t = 1 , Vi = 0 )
Thus distance in final second = 7 × 5 = 35 mnemonic
Hence the final velocity in final sec = Vf = 35 m/s
from 1st eq of motion Vf = Vi ± at
it implies that 35 = 0 ± 10t
So t = 35/10 = 3.5 s
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