Question

A body dropped from the top of a tower acquires a velocity of 20m/s on reaching the ground. Calculate the height of the tower.

Answer 1

Answer:

The height of the tower will be 20.41 m.

Explanation:

Given that,

Velocity v = 20 m/s

Using equation of motion

$v2-u^2=2as$

Here, u = initial velocity

v= final velocity

g = acceleration due to gravity

s = height of the tower

The height of the tower will be

$20^{2}-0=2\times9.8\times s$

$s= \dfrac{400}{2\times9.8}$

$s= 20.41\ m$

Hence, The height of the tower will be 20.41 m.

Answer 2

Answer:

Hope this helps and you get it right