a body dropped from the top of a tower covers 7/16 of the total height in the last sec. of its fall. the time of fall is
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For total height
H = 0.5gT^2
For first 9H/16 Height
9H/16 = 0.5g * (T - 1)^2
Divide above two equations
16/9 = [T / (T - 1)]^2
T / (T - 1) = 4/3
3T = 4T - 4
T = 4 seconds
Time of fall is 4 seconds
H = 0.5gT^2
For first 9H/16 Height
9H/16 = 0.5g * (T - 1)^2
Divide above two equations
16/9 = [T / (T - 1)]^2
T / (T - 1) = 4/3
3T = 4T - 4
T = 4 seconds
Time of fall is 4 seconds
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