a body dropped from the top of a tower covers a distance 7x in the last second of its journey ,where x is the distance covered in first second.How much time does it take to reach the ground?
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Answer: 3.5 sec
Explanation: distance covered by a free falling body in one sec = 5
( from s = Vit ± 1/2 × a × t (square)
putting a = g , t = 1 , Vi = 0 )
Thus distance in final second = 7 × 5 = 35 mnemonic
Hence the final velocity in final sec = Vf = 35 m/s
from 1st eq of motion Vf = Vi ± at
it implies that 35 = 0 ± 10t
So t = 35/10 = 3.5 s
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Answer: 4s
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