Question

A body dropped from top of a tower fall through
40 m during the last two seconds of its fall. The
height of tower is (g = 10 m/s²)
(a) 60 m (b) 45 m
(c) 80 m (d) 50 m

Answer 1

Answer:

Explanation:

Let the height of tower is h.

Consider velocity of body when it reaches a height of h-40 be v.

40 = v×2 + 1/2×g×4

40 = v×2 + 20

v = 10 m/s

v^2 -u^2 = 2g( h - 40 )

100 = 2×10( h - 40 )

h = 45 m