Physics, asked by vanditbadjatiya7311, 10 months ago

A car moves a distance of 200 m. It covers the
first half of the distance at speed 40 km/h and
the second half of distance at speed v. The
average speed is 48 km/h. Find the value of v
(a) 56 km/h (b) 60 km/h
(c) 50 km/h (d) 48 km/h

Answers

Answered by Anonymous
7

HEY MATE YOUR ANSWER IS HERE...

TOTAL DISTANCE = 200 m

1st HALF DISTANCE SPEED = 40 Km / h

2nd HALF DISTANCE SPEED = X Km / h

AVERAGE SPEED = 48 Km / h

NOW ,

AVERAGE SPEED =

TOTAL DISTANCE / TOTAL TIME

NOW ,TOTAL TIME =

speed \:  =  \frac{distance \: }{time}  \\  \\ time \:  =  \frac{distance}{speed}

NOW TOTAL TIME =

 \frac{100}{40}  +  \frac{100}{v}

HENCE ,AVERAGE SPEED =

 48 \: =  \frac{200}{ \frac{100}{40} +  \frac{100}{v}  }

  \frac{1}{24} =  \frac{1}{40}  +  \frac{1}{v}  \\  \\ v =  \frac{120}{5 - 3}  \\  \\ v =  \frac{120}{2}  \\  \\ v = 60 \: </strong><strong>km\</strong><strong>:</strong><strong> </strong><strong>per </strong><strong>\</strong><strong>:</strong><strong> </strong><strong>hrs</strong><strong>

HENCE OPTION (B) IS CORRECT

THANKS FOR YOUR QUESTION HOPE THIS HELPS

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