Question

A body executes SHM along y-axis it's displacement varies with time according to the equation
y=1.5 sin (100 vt) where 'Yis in meter and T in seconds. Calculate the amplitude, period and
frequency of motion of the particle.​

Answer 1

Answer:

y=Asin(wt+Kx)

here amplitude is 1.5

w=100

(w=2Π÷t)

100=2Π÷t

t=2π÷100

t=π÷50

so,time period is π/50

f=1/t

f=50/π

so,frequency of the particle is 50/π