Question

A body executing shm has a maximum acceleration equal to 24 m per second square and maximum velocity equal to 16 metre per second to the amplitude of shm is

Answer 1

Max. acc. = w²A = 24
Max. v = Aw = 16
w= 16/A
Put the value of w in w²A:-

24 = A x 16/A x 16/A
24 = 256/A
24A = 256
A = 256 / 24 = 10.66m

Answer 2

Answer:

32/3

Explanation:

Given maxx. Accln. (w^2. a) = 24m/sec^2. ..... (1)

Maxx. Vel. (w. a) = 16m/sec

Putting the value of w in eqn. (1), we get,

24 = a. (16/a). (16/a)

Or, 24 = 256/a

Or, a = 256 / 24

Or, a = 32/3

(this is a quite easy problem in comparison to JEE Mains)