a body fall freely from rest.find distance it falls in 3 seconds
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Answered by
1
a = 9.8 m/s²
u=0
t= 3 sec
s = ut+1/2at²
s= 0 +1/2×9.8 × 3×3
s= 44.1 m
u=0
t= 3 sec
s = ut+1/2at²
s= 0 +1/2×9.8 × 3×3
s= 44.1 m
Answered by
0
As acceleration for free falling body is = 9.8 m/s square
U=0 ( given as it starts from rest)
T=3 sec (given)
S=ut+1/2 at square
=1/2×9.8×3×3
=44.1m
Plz mark as brainliest if it helped you
U=0 ( given as it starts from rest)
T=3 sec (given)
S=ut+1/2 at square
=1/2×9.8×3×3
=44.1m
Plz mark as brainliest if it helped you
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