Question

A body falling for 2s, covers a distance equal to that covered in the next second:

a)30m
b)10m
c)60m
d)20m

answer it with explanation

Answer 1

distance travelled by the body in 2 seconds is,s=ut+12gt2 =u×2+12×g×2×2 =2u+2g


(i)Distance travelled by the body in next second is,s=u+g22n-1 =u+g22×3-1 =u+5g2
(ii)Since, the body covers equal distance,

so from equation (i) and (ii),
2u+2g=u+5g2
or, u=g2
Now putting the value of u in equation (i), we get,
s=2u+2g
=2×g2+2g
=3g=3×10=30 m . option a is correct answer --- I hope it helps u

Answer 2

s=ut+1/2at sq

s=?

u=0

g=10

t=2sec

s=0(2)+1/2(10)2sq

s=2+25sq

s=27sq