A body falling freely to a height of 10m goes into
sand 1 mm. The retardation of the body in sand
is :
(a) 1000 g
(b) 100 g
(c) 10 g
(d) 1 g
if anyone know the solution please explain it
Answers
Answered by
3
2as = v² - u²
2×9.8×1000 = v²
9800×2 = v²
v = √19600 = 140 mm/s
2as = v² - u²
2×a×1 = 0 - 19600
2a = -19600
a = -9800mm/s
Acceleration = -9.8m/s
Answered by
0
Answer:9.8 m/
Explanation:
2as = v² - u²
2×9.8×1000 = v²
9800×2 = v²
v = √19600 = 140 mm/s
2as = v² - u²
2×a×1 = 0 - 19600
2a = -19600
a = -9800mm/s
Acceleration = -9.8m/s
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