Question

A body falling freely under gravity passes two points 30 m apart in 1s. find from what point above the upper point it began to fall ? (g=9.8m/s2)

Answer 1

Answer:

Answer is given above.

Answer 2

32.1 m is the point above the upper point at which it began to fall

Explanation:

Let the body passes the upper point at t

and the second and lower point at (t + 1) s,

then:

$S_{2} - S_{1}$ = 1/2g$(t - 1)^{2}$ - 1/2$gt^{2}$

= 1/2g(2t + 1)

By taking g = 9.8 $m s^{2}$

or 30 m = 1/2 × 9.8(2t+1)

∴ t = 2.56 s

and thus, S1 = 1/2$gt^{2}$

= 1/2×9.8 * $(2.56)^{2}$

 = 32.1 m.

Learn more: gravity

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