Question

A body falling from rest on a planet covers 3 m in 1 s. What is the time period of a simple pendulum of length 96 cm on this planet?

A) 3π/5

B) 4π/5

C) π

D) 2π
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Answer 1

Answer:

h=0.5at^2

3=0.5a

a=6 m/s2

T=2π√(l/a)

T=2π√(0.96/6)

T=2π x √0.16

T=2π x 0.4

hence

T=4π/5

B is correct