A body falling from the height of 10 m rebounds from a hard floor. It loses 20% of its energy in input what will be coefficient of restitution ?
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From given data:
KE after collision = (1 - 20%) * KE before Collision.
= 0.80 * KE before collision.
Coefficient of restitution = e
e = (relative velocity after collision)
/ (relative velocity before collision)
e² = Kinetic Energy after collision
/ Kinetic energy before collision
= 0.80
e = 0.894
The height from which the ball falls does not matter for calculating e.
This is a quick way of calculating e, rather than finding the velocities first and then taking their ratio.
KE after collision = (1 - 20%) * KE before Collision.
= 0.80 * KE before collision.
Coefficient of restitution = e
e = (relative velocity after collision)
/ (relative velocity before collision)
e² = Kinetic Energy after collision
/ Kinetic energy before collision
= 0.80
e = 0.894
The height from which the ball falls does not matter for calculating e.
This is a quick way of calculating e, rather than finding the velocities first and then taking their ratio.
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