If in stopping a car of mass 800 kg by applying brakes, 4.18 kcal of heat is produced ,then what was the speed of the car before applying the breakes?
Answers
Answered by
23
(mv^2)/2 = 41.8 × 10^3 × 4.184.
v^2 = 174891.2 / 800 = 218.614.
Therefore,
v = 14.7856 m/s^2.
v^2 = 174891.2 / 800 = 218.614.
Therefore,
v = 14.7856 m/s^2.
YashP9494:
Is it correct?
i have written the question wrong...instead of 4.18 kcal it will be 41.8 kcal
Oh no....hahaha
u can solve it again
Is it correct now?
no the anwer is not matching with my book
Oh sorry, I forgot to multiply with 2...
The answer should be 20.91 m/s
Answered by
50
Q=1/2mv^2
Q=41.8*4180=174724J
174724=1/2*800*v^2
v^2=436.8
v=20.9m/s
which is the answer
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