Question

A body falls for 4sec from rest. It the acceleration due to gravity of earth ceases to act, the distance it travels in the next 1sec is
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Answer 1

Answer:

Initially the body starts its motion from rest therefore u = 0. Let journey be 'A' when a acceleration of earth is acting on the body time = 4 seconds let's find 'v'.

$\purple{v = u + at}$

v = 0 + 9.8 × 4

v = 39.2 m/s

When acceleration stops acting the velocity of the body is 39.2 m/s . Now the distance traveled by the body in next 1 sec.

$\purple{s = ut + \frac{1}{2} a {t}^{2}}$

$s \: = \: 39.2 \times1 + \frac{1}{2} \times 0 \times {t}^{2} \\ \\ s = 39.2 \times 1 \\ s = 39.2m$

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