Question

A body falls freely crosses the points A and B at time intervals 4 sec and 6 sec from starting. Then the distance between the points 'A' and 'B' is [g=acceleration due to gravity] 1) 10g 2) 15 g 3) 17 g 4) 20 g​

Answer 1

Answer:

I think your question is wrong it may be : A body is falling freely from a point A at a certain height from the ground and passes through point B,C and D (vertically as shown) so that BC=CD. The time taken by the particle to move from B to C is 2 seconds and from C to D is 1 second. Time taken to move from A to B in second is

Explanation:

Answer is : 0.5

BC=2V+

2

g

×2

2

BC=2V+2g

2BC=3V+

2

1

g×3

2

2BC=3V+

2

9g

4V+4g=3V+

2

9g

V=

2

9g

−4g

=g/2

A→B

V=u+at

2

g

=0+g×t

t=1/2