Write the name of the test of congruence by which the following triangles are congruent
Answers
Answer:
If all the three sides of one triangle are equivalent to the corresponding three sides of the second triangle, then the two triangles are said to be congruent by SSS rule. In the above-given figure, AB= PQ, QR= BC and AC=PR, hence Δ ABC ≅ Δ PQR.
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Answer:
If all the three sides of one triangle are equivalent to the corresponding three sides of the second triangle, then the two triangles are said to be congruent by SSS rule.
Step-by-step explanation:
- Know what congruency in the triangle is. Congruence is the property of triangles by which we can compare that the two triangles have the same corresponding sides and corresponding angles. The two triangles are said to be congruent if all the three sides and the three angles are equal.
- We know that there are five rules of congruency, which are as follows:
- SSS rule (Side- Side-Side): According to this property if all the corresponding sides of two triangles are equal, the triangles are congruent.
- SAS rule (Side-Angle-Side): According to this rule, the corresponding sides and the included angle for the two triangles must be equal in order to be congruent.
- ASA rule (Angle-Side-angle): According to this rule, two angles and the included side for the two triangles, must be equal. Then the two triangles would be congruent.
- AAS rule (Angle-Angle-Side): According to this rule, two angles and one non-included side for the two triangles, must be equal. Then the two triangles would be congruent.
- RHS rule (Right Angle-Hypotenuse-Side rule): This rule says that two-right angled triangles will be congruent if the hypotenuse and one side for two triangles are equal.
- These are rules or tests for congruency of a triangle, apart from these five any other rule would not be followed.
SSS (Side-Side-Side)
If all the three sides of one triangle are equivalent to the corresponding three sides of the second triangle, then the two triangles are said to be congruent by SSS rule.
In the above-given figure, AB= PQ, BC = QR and AC=PR, hence Δ ABC ≅ Δ PQR.
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