Question

A body Falls freely under Gravity starting from rest find the ratio at the distance travelled by it during the first half of any interval of time the distance travelled during the second half of the same interval

Answer 1

Answer:s1/s2= 1/3

Explanation:

Here u=0

Let t= the time interval

If s1= the distance covered in time t/2

S1=0*t/2+1/2g(t/2)^2=1/8gt^2......(1)

Let s= the distance covered in t second from the beginning

S=0*t+1/2*gt^2 or. S=1/2gt^2

If s2= distance covered in last t/2 second.

S2=s-s1= 1/2gt^2-1/8gt^2

Or s2= 3/8gt^2.....(2)

From equation (1) and (2), s1/s2=1/8gt^2*8/3gt^2

Or s1/s2=1/3.