Question

a body falls from a height of 500 metres in how much time will it strike the ground

Answer 1

given h= 500 m

using eqn. h= ut + 1/2 gt^2 where u is initial velocity and u=0m/s

we get h= 1/2 gt^2

thus t = 10 second ( putting g= 10 m/s)

Answer 2

Explanation:

Let acceleration = 10m/s^2

Distance is 500m

Initial velocity 0m/s

S= ut+1/2at^2

500= 0+1/2 ×10 (t)^2

(t)^2 = 500/5

= 100m

t= 10 sec

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