A body falls from rest .The velocity acquired by falling a distance 2h is
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Here,
initial velocity,u=0
distance=h.
We use the formula,
v^2-u^2=2gh………….(1) Then,
v=(2gh)^1/2…………….(2)
When body moves further distance h, the total distance is 2h. Therefore,
v’=(4gh)^1/2=(2)^1/2v
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