Question

A body falls from rest .The velocity acquired by falling a distance 2h is ​

Answer 1

Here,

initial velocity,u=0

distance=h.

We use the formula,

v^2-u^2=2gh………….(1) Then,

v=(2gh)^1/2…………….(2)

When body moves further distance h, the total distance is 2h. Therefore,

v’=(4gh)^1/2=(2)^1/2v

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