Question

A body floats with one third of its volume outside water and three fourth of its volume outside a liquid density of liquid is

Answer 1

Let the Volume of the Body be V and the density of the body be d.

Now, we know that,

density of water = 1000 kg/m3

weight of the body in air = w = V × d₁ × g

Upthrust or Buoyant force acting on a object = 2V/3 × d₁ × g

Now, let the density of another liquid be d₂.

Volume of body inside water= V- 3V/4= V/4

Upthrust acing on an object = (V/4)d₂g

Since, Body floats on surface, therefore,

2V/3 × d₁ × g = (V/4) × d₂ × g

d₂ = 8000/ 3

d₂ = 8 /3 x 10³

Hope it helps.

Answer 2

Answer:

8/3g/cc

Explanation:

through the ratio of the submerged volume.