A body has -80 micro coulomb of charge. Number of additional electrons in it will be?
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Answer:
5*10¹⁴ electrons
Explanation:
q=-80μC=-80*10⁻⁶C
qe(charge or electron)=-1.6*10⁻¹⁹
N(number of electrons)=q/qe=80*10⁻⁶/1.6*10⁻¹⁹=5*10¹⁴electrons
Hope it helps!
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