Question

a body has - 80 microcoulomb of charge. no of additional electrons on it will be

Answer 1

Answer

5×10¹⁴

Explanation:

Q=ne ⇒n=Q/e=80×10⁻⁶/1.6×10⁻¹⁹ =5×10¹⁴

Answer 2

The number of additional electrons on the body is $5\times 10^{14}$.

Explanation:

It is given that,

Charge in a body, $q=80\ \mu C=80\times 10^{-6}\ C$

If n is the number of additional electrons. It can be calculated using quantisation of charges as :

$q=ne$

e is the charge on an electron

$n=\dfrac{q}{e}$

$n=\dfrac{80\times 10^{-6}}{1.6\times 10^{-19}}$

$n=5\times 10^{14}$

So, the number of additional electrons on the body is $5\times 10^{14}$. Hence, this is the required solution.

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