Physics, asked by manviChandiwala, 9 months ago

A body has a constant acceleration of 2 m/s2 starting from rest. a. How fast is it going after 5 s? b. How far has it traveled in 5 s? c. How far has it traveled by the time that its velocity has reached 40 m/s?

Answers

Answered by Prakashroy
1

GIVEN

Acceleration, a = 2m/s2

Starts from rest, so, initial velocity, u = 0m/s

  1. ANSWER TO PART 1 OF THE QUESTION -

To Find

Velocity of the body after 5s

Answer:-

Using the equation of motion,

v = u + at

where v = final velocity (to be found out in this question)

v = 0 + 2 × 5

v = 10m/s (Ans)

2. ANSWER TO PART 2 OF THE QUESTION -

To Find

Distance travelled in 5s.

Answer:-

Using the equation of motion,

s = ut +  \frac{1}{2} a {t}^{2}

where, s = Distance travelled ( to be found out in this question)

s = 0 × t +1/2 × 2 × 25

s = 25m (Ans)

3. ANSWER TO PART 3 OF THE QUESTION -

To Find

Distance travelled when it's speed had reached 40m/s.

Answer:-

v = u + at

40 = 0 + 2t

t = 20s

s = ut +  \frac{1}{2} a {t}^{2}

s = 0 × 1/2 × 2 × 400

s = 400m (Ans)

[THANK YOU]

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