Question

a body has an acceleration of 2m/s starting from rest . how fast is it going after 5 sec​

Answer 1

Answer:

10 m/s

Explanation:

u= 0 (starting from rest)

t = 5 s

a = 2 m/s²

v=?

to find v using 1st equation of motion

v = u + at

v = 0 + 5*2

v = 10

therefore v = 10 m/s.

Answer 2

Answer: 10 m/s

Explanation:

Given,

Acceleration(a) = 2 m/s²

As body has started from rest So,

Its,

Initial Velocity (u) = 0

Time (t) = 5 sec

To find the distance velocity after 5 second , We shall use 1st equation of motion. If the velocity after 5 second is v

v = u + at

v = 0 + 5×2

v = 10 m/s

Note:- Equation of motion are as follows,

v = u + at

s = ut + (1/2 × at²)

v² = u² + 2as

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