Question

a body has an initial velocity of 3m/s and has an acceleration of 1m/s^2 direction normal to the of initial velocity. The velocity of the body after 4 sec ?

Answer 1

u = 3
a = 1
and t=1 .
Then we find v from 1 eq. of motion.
And then Using t=4 We can easily find the velocity of the body ...
Pls.... mark as braineist answer...

Answer 2

Given:

The initial velocity u= 3 m/sec

The acceleration a=1 m/sec²

The time is t= 4 sec

To find:

The velocity after 4sec

Solution:

We have the formula of net velocity

V=$\sqrt{u^{2}+ v^{2} }$

Where v is velocity in y direction = at=1×4= 4 m/sec

Put the value back in above equation.

V=$\sqrt{9+16}$

V=√25

V=  5 m/sec

The velocity after the 4 sec is 5 m/sec