Question

A body has initial velocity of 3 m/s and has an
acceleration of 2 m/s². The distance travelled
by it in 5 s and its velocity is
(A) 40 m, 13 m/s (B) 10 m, 13 m/s
(C) 40 m, 10 m/s (D) 10 m, 10 m/s​

Answer 1

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Given :

Initial velocity, u = 3 m/s

Acceleration, a = 2 m/s²

Time taken, t = 5 seconds

To find :

Final velocity, v

Distance travelled, s

According to the question,

➟ v = u + at

Where,

v = Final velocity

u = Initial velocity

a = Acceleration

t = Time taken

➟ v = 3 + 2 × 5

➟ v = 3 + 10

➟ v = 13

So, the final velocity is 13 m/s.

Now,

➟ s = ut + ½ at²

Where,

s = Distance travelled

u = Initial velocity

a = Acceleration

t = Time taken

➟ s = 3 × 5 + ½ × 2 × 5 × 5

➟ s = 15 + 25

➟ s = 40

So, the distance travelled by the body is 40 m.

Hence, option (A) 40 m, 13 m/s is correct.

Answer 2

Answer:

In x direction, Vx=3m/s

In y direction, Vy=at=1(4)=4m/s.

Vnet=Vx2+Vy2=32+42=5m/s

at an angle tan−1(4/3) with initial direction of velocity.