A body having 45m/s is retarding with 9m/s^2. how much time it will take to stop
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Answered by
2
in this ques acceleration =9m/s^2
initial velocity=45m/s
final velocity=0
so,a=v-u/t
9=0-45/t
9t=-45
so t=-45/9
that is time =5minutes
initial velocity=45m/s
final velocity=0
so,a=v-u/t
9=0-45/t
9t=-45
so t=-45/9
that is time =5minutes
Answered by
2
v = 0
u =45
a= -9
v = u + at
0 = 45 +(- 9)t
-45 = -9t
t = 45/9
t = 5 seconds
u =45
a= -9
v = u + at
0 = 45 +(- 9)t
-45 = -9t
t = 45/9
t = 5 seconds
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