Question

A body having an excess of 10 ^6 electrons is placed in an electric field of 1000 n /c towards east. find out the magnitude and direction of the force acting on the body.

Answer 1

Answer:

Electric force, F = 1.6 × 10⁻¹⁰ N and its direction is inwards

Explanation:

It is given that,

Number of electrons, e = 10⁶

Total charge, $q=1.6\times 10^{-19}\times 10^6\ C=1.6\times 10^{-13}\ C$

Electric field, E = 1000 N/C

Electric force is given by the product of electric charge and electric field.

i.e. F = q E

$F=1.6\times 10^{-13}\ C\times 1000\ N/C$

$F=1.6\times 10^{-10}\ N$

As the electrons are negatively charged particles. The direction of electric filed for electrons is negative.

Answer 2

Answer:

Electric force, F = 1.6 × 10⁻¹⁰ N and its direction is inwards.

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