A body having mass 100kg is suspended from a horizontal bar with the help of two string .The string makes angle 30degree and 60 degree with the horizontal direction .Find the tension on the string.(g=10m/s)
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mgsin theta= Tension
T¹=1000×1/2=500N
T²=1000×√3/2=500√3 N
T¹=1000×1/2=500N
T²=1000×√3/2=500√3 N
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