A body having uniform acceleration of 10 ms-2 has a velocity of 100 ms-. In what time its velocity will
doubled?
(SGD 2018
(A) 8 sec
(B) 10 sec
(C) 12 sec
(D) 14 sec
(C)
Xi Zero
Answers
Answer:
Accelerarion (a)=10m/s^2
Final velocity(v) =100m/s
It is understood that initial velocity (u)= 0
According to the first kinematical equation,
v = u +at
100 = 0+10t
t=100/10
t=10 s…….(1)
Similarly,
When v is doubled= 2v =2×100= 200m/s,
v=u +at
200= 0 +10t
t= 200/10
t=20 s …..(2)
Therefore, time taken to double the velocity
=20 -10
=10 s
Hence, the time taken to double the velocity is 10s.
Answer:
Acceleration (a)=10m/s^2
Final velocity(v) =100m/s
It is understood that initial velocity (u)= 0
According to the first kinematical equation,
v = u +at
100 = 0+10t
t=100/10
t=10 s…….(1)
Similarly,
When v is doubled= 2v =2×100= 200m/s,
v=u +at
200= 0 +10t
t= 200/10
t=20 s …..(2)
Therefore, time taken to double the velocity
=20 -10
=10 s
Hence, the time taken to double the velocity is 10s.
Explanation: