Physics, asked by nayandeep125, 11 months ago

a body if mass 10 g moves with constant speed 2m/s along a regular hexagon. The magnitude of change in momentum when the body crosses a corner is :
A 0.04 kg m/s
B zero
C 0.02 kg m/s
D 0.4 kg m/s

Answers

Answered by Vishal101100
2

Answer:

option c will be correct.

Solution :-

Mass = 10g = 1/100 kg = 0.01 kg

And velocity = 2m/s

then .

Momentum(P) = m×v = 0.01×2

= 0.02 kg m/s Answer....

Answered by Thinkab13
7

Answer:

As we know,

1kg = 1000g

hence,1g=1/1000kg

so for, 10g=10/1000=1/100kg

Now we know,

Momentum=mass * velocity

=1*2/100

=0.02kgm/s

Hence option c is correct

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