Question

a body if thrown up with a velocity 29.23m/s.Distance travelled in last second of upward motion

Answer 1

Assuming the body will fall and terminal velocity is not reached, find out the distance it will travel up by using v² = u²+2as where v² is 0 and a is -9.81 Then use the the same distance again in the same equation to find the ending velocity v v² = u²+2as where u² is 0 and a is 9.81 Note :- Dont mess up the signs of acceleration

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