Question

A body initially at rest explodes into 2 pieces of mass 2M and 3M respectively having a total kinetic energy E. The kinetic energy of piece of mass 2M after the explosion is?​

Answer 1

Explanation:

Conservation

2mv1+3mv2=0

Energy E =12(2m)v21+12(3m)v22

Solving for v1,v2v21=35Em,v22=415Em

hence

E1=35ENOTE{2mv1+3mv2=0E=12(2m)21+12(3m)vor

{2v1+3v2=0Em=v21+32v22or{4v21=9v22Em=v212

and solving for v21,v2 we get v21=35Em,v22=415Em