Question

f(x, y) = sin(y + yx2) / 1 + x2 Value of fxy at (0,1) is

Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

Answer:

The required value of the function at (0,1) is found to be 0.841.

Step-by-step explanation:

The given function is of two variable and its expression is given by:

$f(x,y)=\frac{sin(y+yx^2)}{1+x^2}$

The given point for the calculation of function f(x,y) is at the coordinate (0,1).

For find the value of f(x,y) at (0,1), we need to substitute this point in the function's expression and calculate the resulting value.

Thus, substituting the point (0,1) in the given function's expression, we get:

$f(x,y)=\frac{sin(1+1(0)^2)}{1+(0)^2}$

Simplifying this, we get:

$f(x,y)=\frac{sin(1)}{1}$

Or we can say:

$f(x,y)={sin(1)}$

Finding the value of sin(1), we get:

$f(x,y)=0.841$

Thus, the value of the given function at (0,1) is found to be 0.841.