A body initially at rest starts moving with a constant acceleration 2 m/s2 . Calculate 1 the velocity acquired and 2 the distance travelled in 5 second
Jessfermion:
v = 10m/s and S = 25m
Answers
Answered by
32
u=0 a=2 m/s*s t=5sec
. v=u+at =0+2*5= 10m/s
. S=(v^2-u^2)/2*a= (100-0)/2*2=100/4=25 m
. v=u+at =0+2*5= 10m/s
. S=(v^2-u^2)/2*a= (100-0)/2*2=100/4=25 m
Answered by
10
v = 10m/s. and. s = 25m
Similar questions
English,
7 months ago
Economy,
7 months ago
Business Studies,
7 months ago
CBSE BOARD X,
1 year ago
English,
1 year ago
English,
1 year ago
English,
1 year ago