Question

A body, initially at rest, starts moving with a constant acceleration 2m/s^2. Calculate
-the velocity acquired
-distance travelled in 5s​

Answer 1

ANSWER:-

GIVEN:-

u=0

a=2m/s²

t=5s.

FIND:-

the velocity acquired.

CALCULATION:-

[formula ]

a=(v-u) /t

2m/s²=(v-0)/5s

10m/s=v-0

.°. v=10m/s.

HENCE,

THE velocity acquired is 10m/s.

FIND:-

distance travelled in 5s.

d=ut+1/2at²

d=0+1/2×2(5)²

✨✨✨✨d=25m✨✨✨✨

.°.distance travelled in 5s is 25m.

✨✨THANKS✨✨

Answer 2

Answer:

Given:

Car starts from rest !!

Acceleration = 2 m/s²

To find:

Velocity and distance travelled in 5 secs.

Calculation:

Let final Velocity be v, initial velocity be u , time be T and acceleration be a

v = u + at

=> v = 0 + (2 × 5)

=> v = 10 m/s

Distance be denotes as D

D = ut + ½at²

=> D = 0 + ½(2)5²

=> D = 25 metres.