Question

A body initially at rest travels a distance 100m in 5s with a constant acceleration. Calculate:
i. The acceleration
ii. Final velocity at the end of 5sec

Answer 1

Explanation:

● distance (s) = 100m , initial velocity (u) = 0 , time (t) = 5

here acceleration is constant so equations of motion can be used

● using third equation of motion

s = ut + at^2 /2

here s is distance, u is initial velocity, a is acceleration, t is time

100 = 0(5) + a(5^2)/ 2

100 = 0 + 25a /2

100×2 = 25a

a = 8m/s^2

here in second case time is given, acceleration is there and initial velocity is also given

so 1st equation of motion can be applied

● v = u +at

where v is final velocity , u is initial velocity , a is acceleration and t is time

v = 0 + 8(5)

v = 40m/s