Question

a body intially at rest starts moving a constant acceleration of 2ms-2. Calculate the velocity acquired and the distance travelled in 5 sec

Answer 1

Answer:

Answer is 10ms-1

Explanation:

By using the equation v=u+at

we have u=0; a=2; t=5; v=?

v=0+2×5

v=10

Answer 2

Answer:

we have,

u=om/s

a=2m/s^2

t=5s

using 1st equation of motion

v=at

2*5=10m/s

using 2nd equation of motion

s=1/2at^2

1/2*2*5*5

=25m/s^2