Physics, asked by bvnamrutha246, 10 months ago

A body is at 30°F. A faulty celsius thermometer reads it as 4°C. If ice point of faulty thermometer is 5°C the steam point on
it will be
(A) 98°C
(B) 90°C
(C) 95°C
(D) 100°C
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Answers

Answered by abhi178
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A body is at 30°F. A faulty Celsius thermometer reads it as 4°C. if ice point of faulty thermometer is 5°C.

To find : the steam point will be...

solution : ice point of faulty thermometer = 5°C

let steam point of faulty thermometer = X °C

in Fahrenheit thermometer,

ice point = 32°F

steam point = 212°F

now \quad\frac{T_{read}-T_0}{T_{steam}-T_0}=\frac{F_{read}-F_0}{F_{steam}-F_0}

⇒(30°F - 32°F)/(212°F - 32°F) = (4°C - 5°C)/(x - 5°C)

⇒-1/90 = -1/(x - 5)

⇒x - 5 = 90

⇒x = 95°C

Therefore the steam point of faulty thermometer is 95°C .

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