a body is coming down an inclined plane with an acceleration of 1 M per second square if it starts from rest find the time after which its velocity becomes 5 metre per second
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You can use the formula:
s=ut+1/2at^2
where s=distance travelled
u=initial velocity
a=acceleration
t=time
ATQ, u=0m/s(as the body starts from rest, thus it's obvious that the initial velocity will be 0),t=20s, a=5m/s^2, s=?
Now put the value in the formula:
s=ut+1/2at^2
s=0(20s)+ 1/2(5m/s^2)(20s)^2
s=0+1/2(5m/s^2)(400s^2)
s=1/2(2000m)
s=1000m
Thus, distance travelled is 1000m
s=ut+1/2at^2
where s=distance travelled
u=initial velocity
a=acceleration
t=time
ATQ, u=0m/s(as the body starts from rest, thus it's obvious that the initial velocity will be 0),t=20s, a=5m/s^2, s=?
Now put the value in the formula:
s=ut+1/2at^2
s=0(20s)+ 1/2(5m/s^2)(20s)^2
s=0+1/2(5m/s^2)(400s^2)
s=1/2(2000m)
s=1000m
Thus, distance travelled is 1000m
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