A body is dropped from a balloon which is moving upward with a speed of 10m/s.The body is dropped when the balloon is at a height of 390m from the surface of earth.Find the approximate time taken by the body to reach the surface of earth.Take g=10m/s2.
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Explanation:
First, we write all the known quantities
a=-10m's^2.
s=390m
u=+10m/s
s=ut+1/2at^2
s 10t+5t^2
-390=10t+5t^2.
-78=2t=78=0
d=b^2-4ac.
d=4+312.
d=316.
-b+-root d/2a.
2+-2root 79/2=1+-79.
therefore time taken to hit the ground will be 1+79.
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