Question

A body is dropped from a certain height and acquired a speed of 20ms-1
when reaches the ground .find height​

Answer 1

Explanation:

given that the body is dropped so that initial velocity is

zero

u = 0

given v = 20m/s

here g is +ve because the motion is downward and

acceleration is also downward

so using 2nd equation of motion

v^2 - u^2 = 2gs ( here in this case s is height)

20^2 - 0^2 = 2( 9.8) (s) g is acceleration due to

gravity and its value is 9.8m/s^2

400 - 0 = 19.6 (s)

400 / 19.6 = s

s = 20.4 m

Answer 2

Answer:

here ur anwer hope it is helpful