Question

A body is dropped from a height 300 m and at the same time another stone is projected vertically upwards with velocity 100 m/s find when and where they meet each other

Answer 1

they would meet after three second

$relatively \: acceleartion = 0 \\ time = \frac{dist}{time} = \frac{300}{100}$

now second equation of motion se

$s = ut + \frac{1}{2} a {t}^{2} = 0 + 5 \times {3}^{2} = 45m$