Question

a body is dropped from a height 45m. another body is projected downwards from the same height 1 second later. if both the bodies reach ground at the same time . find the speed of projection of the second body

Answer 1

Answer:

here is your answer.....

Answer 2

Answer:

Velocity of projected body is -12.5m/s

Explanation:

Given that,

One body is dropped from a height if 45m and other body is projected vertically downward after 1 sec

Both bodies reach ground in same time.

The time taken by dropped body to reach ground is

$t = \sqrt{\frac{2h}{g} } = \sqrt{ \frac{2 \times 45}{10} } = 3sec$

Therefore,time taken by projected body to reach ground is

$3 - 1 = 2sec$

Using the equation of motion for downward projected body,we get

$h = ut - \frac{1}{2} gt {}^{2} \\ = > - 45 = u(2) - 5(2 {}^{2} ) \\ = > u = - 12.5ms {}^{ - 1}$

Negative sign indicates velocity is in downward direction.

Therefore,velocity of projected body is -12.5m/s

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