Question

a body is dropped from a height h after it has fallen a height h it would posses ​

Answer 1

Explanation:

You can simply use the equation

S=ut+(1/2)at^2 to falling direction

S=H(that is the displacement to be travelled by the body)

u=0 (the ball has dropped from the rest)

a=g ( the acceleration of the body equal to the acceleration due to gravity)

t= T (time taken for body to reach the ground)

Since u=0, H=(1/2)g(T^2)

T =√(2H/g)