Question

A body is dropped from a height h at t = 0, with zero initial velocity. Its average velocity during the journey is

Answer 1

√(gh/2)  = √(5h)   is average velocity during the journey if A body is dropped from a height h at t = 0, with zero initial velocity

Explanation:

A body is dropped from a height h at t = 0

u = 0  

distance covered s = h

a = g  

Using

S = ut +(1/2)at²

=> h = 0  + (1/2)gt²

=> t² = 2h/g

=> t  = √(2h/g)

Average Velocity = Distance/time = h/t   =  h/√(2h/g)   = √(gh/2)

using g = 10  => Average Velocity = √(5h)

or

Using V =  u + at

=> V =   0 + g √(2h/g)

=> V = √(2gh)

or using  V² - U² = 2aS

=> V² - 0  = 2gh

=> V = √2gh

Average Velocity  =  ( u + V)/2  =   ( 0 + √(2gh))/2 = √(gh/2)

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